A Sphere Is Inscribed In Where The Diameter Of The Sphere And Cylinder Are Equal And Height Of The Cylinder Is 2r.Find The Formula For The Volume Of T
A sphere is inscribed in where the diameter of the sphere and cylinder are equal and height of the cylinder is 2r.Find the formula for the volume of the sphere if it is 2/3 of the volume of the cylinder which is πr³h.
Answer:
volume of the sphere is 4π/3 r^3
Step-by-step explanation:
A SPHERE is a solid figure which is round, where the distance from every point on its surface to its center is equal called the RADIUS. One example of a sphere is a tennis ball.
A cylinder on the other hand is another solid figure with a circular base and have a straight parallel sides.
Basing on the problem, the sphere is inside the cylinder which radii are equal, and the height of the cylinder as twice its radius.
In most problems, we can solve the VOLUME OF THE SPHERE using the formula
Vsphere = (4/3)(π)(r^3)
But since the problem states that the volume of the sphere is 2/3 of the volume of the cylinder which is also given, then all we have to do is multiply the volume of the cylinder by 2/3.
Vsphere = (2/3)(Vcylinder)
Vsphere = (2/3)(π)(r^2)(h)
Recall that the height of the cylinder is twice the radius, h= 2r. Substituting the value of h to the equation above, we have
Vsphere = (2/3)(π)(r^2)(h)
Vsphere = (2/3)(π)(r^2)(2r)
Vsphere = (2/3)(π)(2r^3)
Vsphere = 4π/3 r^3
Therefore, the volume of the sphere is 4π/3 r^3
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